There are two copper blocks sitting in the $\ce{Cu(NO3)2 (aq)}$ solution, a battery is attached onto both of them, providing enough energy to start the reaction. Since solid pieces of copper are involved, $\ce{Cu}$ must be considered in the reduction potential as well.

2019年3月13日 · The Cu(NO3)2 is an ionic compound with oxidation number “0”. Therefore we know that sum of all the oxidation number of Cu, N and O is equal to 0. 1) the charges of the elements since it is an ionic bond. Cu=+2, N=+5, O=-2. PLZ MARK AS BRAINLEIST

2020年8月23日 · $$\ce{Cu + 4HNO3 -> Cu(NO3)2 + 2NO2 + 2H2O}$$ As we see that with dilute acid oxidation state of nitrogen changes from $+5$ to $+2$ and with concentrated acid it changes from $+5$ to $+4$ but shouldn't it be vice- versa because since concentrated nitric acid is a good oxidizing agent and should show a huge change in oxidation number ?

2023年12月29日 · Name the cations and anions in the following : NH4Cl b) MgO c) Na2SO4 d) CaCO3 e) K4[Fe(CN)6] f) NaOH g) AlCl3 h) Cu(NO3)2 j) FeSO3 k) sodium acetate See answers Advertisement

2022年2月12日 · Cu + 2AgNO3 → Cu(NO3)2+ 2Ag. Explanation: From the given reaction the following things can be determined or indicated. The reaction is a redox reaction. Both oxidation and reduction are taking place simultaneously. Copper is oxidised and silver is reduced. Copper is more reactive than silver

2020年5月4日 · Aqueous Cu(II) is not an strong enough oxidizing agent that it will convert organic matter into carbon dioxide. In other words, it is a weak oxidizing agent. Ascorbic acid is oxidized to dehydroascorbic acid and Cu(II) should be reduced to Cu(I). If you heat the solution strongly, Cu(I) may convert into Cu $_2$ O.

2015年11月3日 · How to balance this redox reaction (using half reaction method): $$\ce{Cu + HNO3 -> Cu(NO3)2 + NO + NO2}$$ You really can't balance this equation for two reasons. (1) There is hydrogen on the left hand side, but none on the right.

2019年9月14日 · Click here 👆 to get an answer to your question ️ Find the formula mass of Cu[NO3]2 vishwassutar1683 vishwassutar1683 14.09.2019

2021年3月12日 · 3cu+2s-2 + 8h+1n+5o-23 → 3s0 + 2n+2o-2 + 3cu(no3)2 + 4h2o Finally, always check to see that the equation is balanced. First, verify that the equation contains the same type and number of atoms on both sides of the equation.

The Cu(NO3)2 is an ionic compound with oxidation number “0”. Therefore we know that sum of all the oxidation number of Cu, N and O is equal to 0. 1) the charges of the elements since it is an ionic bond.